Find the stationary points of y= 5x^2 + 2x + 7
Stationary points occur when the gradient is 0 so when dy/dx =0 therefore we need to find dy/dx.By using 'down and decrease', we bring down the power and multiply by the coefficient and then decrease the power by 1So, dy/dy = (5*2)x^1 + (2)x^0 which simplifies to dy/dx = 10x + 2Setting dy/dx = 0 gives us 10x + 2 = 0. We can rearrange this to get x = -1/5 and sub this back into the original equation to find the y coordinate stationary point= (-1/5, 34/5)
AM
Related Maths A Level answers
All answers ▸Why is the derivative of sin(x), cos(x)?
How do I calculate the eigenvalues and eigenvectors of a 2x2 matrix, and what is the point of doing this calculation?
Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2
A circle C with centre at the point (2, –1) passes through the point A at (4, –5).....