Find the stationary points of y= 5x^2 + 2x + 7
Stationary points occur when the gradient is 0 so when dy/dx =0 therefore we need to find dy/dx.By using 'down and decrease', we bring down the power and multiply by the coefficient and then decrease the power by 1So, dy/dy = (5*2)x^1 + (2)x^0 which simplifies to dy/dx = 10x + 2Setting dy/dx = 0 gives us 10x + 2 = 0. We can rearrange this to get x = -1/5 and sub this back into the original equation to find the y coordinate stationary point= (-1/5, 34/5)
AM
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