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x = i is a solution, and all the coefficients are real, so x = -i must also be a solution:2x^3+3x^2+2x+3 = 0(x+i)(x-i)(Ax+B) = 0 (we argued above that this must be the case)(x^2+1)(Ax+B) = 0(x^2+1)(2x+3) = 0...

1/2 *e^(x)(sin x -cos x)

y=5x 2 -2x+3 Differentiate to find the equation of the gradient of the curve dy/dx=10x-2 Substitute x=0 to find the gradient at the point x=0 dy/dx=-2 y=5 0^2-2 0+3 Substitute x=0 into the original equation ...

In order to answer this question, the expression on the left side of the equation needs to be factorised. This can be done in three stages. 1) finding a factor by subbing in common integers (0, +/- 1, +/-2, ...

Start broad and then narrow down on the question. You could start with an example that explains what the death penalty is and what the issue behind it could be. Then tease your arguments. What could be an ar...