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GCSE or A-level Maths: How can I find the x and y intercepts of a cubic function?
Assume we have the function: y = x ( x 2 + 8x - 9) This function is known as a cubic function as when multiplying out the brackets, the highest function of x would be x 3 .Note: If the highest order of x was...
AM
Answered by
Ahmed M.
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Further Mathematics tutor
16366 Views
Solve these simultaneous equations: 3xy = 1, and y = 12x + 3
From first equation: 3xy = 1 => x = 1/(3y)Substitute expression for x into second equation: y = 12x + 3 => y = 12(1/3y) + 3 = 4/y +3Multiply through by y: y 2 = 4 + 3y => y 2 - 3y - 4 = 0Factorise: ...
HM
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Hallam M.
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Further Mathematics tutor
3143 Views
Solve the following simultanious equations: zy=28 and 2z-3y=13
zy=28 so y=28/z13=2z-3y13= 2z - (28 x 3)/z13=2z-84/zmultiply each side by z to give 13z = 2z 2 -84rearange for a quadratic2z 2 -13z-84=0solve by factorising(2z+8)(z-21/2)z= -4 0r 21/2substitute -4 into both ...
OB
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Oliver B.
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Further Mathematics tutor
2710 Views
Prove that sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5
5 = 5(cos(x)^2 + sin(x)^2) = 5cos(x)^2 + 5sin(x)^2=> 5 - 5cos(x)^2 = 5sin(x)^2=> sin(x)^2 + 5 - 5cos(x)^2 = 6sin(x)^2=> sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5
NT
Answered by
Nicholas T.
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Further Mathematics tutor
2549 Views
Find the coordinates of any stationary points of the curve y(x)=x^3-3x^2+3x+2
A stationary point is a point where the gradient of a curve is 0. The derivative of a curve gives us a function for the gradient at every point on the curve. So we have that dy(x)/dx=0 if and only if the cur...
RS
Answered by
Robin S.
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Further Mathematics tutor
4024 Views
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