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Solve the following system of simultaneous equations: y=x^2 - 5x + 4 ; x+2y=19

Sub y=x^2 - 5x + 4 into x+2y=19x+2(x^2 -5x + 4) = 19x + 2x^2 -10x + 8 =192x^2 - 9x -11 = 0 (2x -11)(x+1) = 0x= 5.5x=-1
SR
Answered by Sulamaan R. • Maths tutor
5024 Views

Solve the quadratic equation, x^2 - 4x -5 = 0

Solve x 2 - 4x - 5 = 0 A very full explanation would be: Start by listing the pairs of numbers that can be multiplied together to get 1 * -5 = -5 (i.e. the coefficient of the first term multiplied by the las...
RH
Answered by Ryan H. • Maths tutor
5612 Views

Solve for y and x, where x=y+1 and y=2x+3

Simultaneous equations: x=y+1 y=2x+3 First solve for x. y=2x+3 so first equation becomes: x=(2x+3)+1 x-2x-3-1=0 -1x-4=0x+4=0 x=-4 Solve for y: y=2x+3 y=2(-4)+3 y=-8+3y=-5
TS
Answered by Tom S. • Maths tutor
4243 Views

Solve the simultaneous equations 2x + y = 7 and 3x - y = 8

There are three methods for solving simultaneous equations: elimination, substitution and by using graphs.Elimination is a good method in this case as the y terms are equal in both equations. We just add the...
TJ
Answered by Tia J. • Maths tutor
7683 Views

How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x 2 +y...
CM
Answered by Chloe M. • Maths tutor
3418 Views