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x^2-9x+20=0

x 2 -9x+20=0x 2 -5x-4x+20=0x(x-5)-4(x-5)=0(x-4)(x-5)=0x-4=0x=4x-5=0x=5
GL
Answered by Georgia L. • Maths tutor
3688 Views

Solve these simultaneously to find values for a and b: 6a + b = 16 and 5a - 2b = 19

In order to tackle questions like this with two letters of unknown value, first what we try to do is eliminate one of the variables completely from an equation. If we call 6a + b = 16 eqn 1 and 5a - 2b = 19 ...
MP
Answered by Malvika P. • Maths tutor
5351 Views

Show that (x + 1)(x + 2)(x + 3) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.

(x+1)(x+2) = ( x^2 + 3x + 2) - multiplying out the first 2 terms(x^2 + 3x + 2)(x + 3) = x^3 + 3x^2 + 2x + 3x^2 + 9x + 6 - multiplying the product of the first two terms by the last termx^3 + 6x^2 + 11x + 6 -...
RK
Answered by Rachel K. • Maths tutor
7372 Views

Find the values of x where x^(2) + 4x + 4 = 0

To solve this question we need to find the values of x which work for the equation x^(2) + 4x + 4 = 0. To solve the equation we can factorise the left-hand side into brackets which will multiply together to ...
BA
Answered by Ben A. • Maths tutor
9268 Views

Solve the simultaneous equations (1) 2x+3y=3 and (2) 3x+2y=7

Remember we can multiply both sides of an equation by the same thing without changing the meaning of the equation. Multiplying equation 1 by 2 gives 4x+6y=6 and multiplying equation 2 by 3 gives 9x+6y=21 . S...
ZL
Answered by Zoe L. • Maths tutor
6135 Views