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How to convert worded problems to solvable inequalities.

Note that in September I am due to start as a trainee maths teacher . For my interview, I taught a lesson on inequalities to a class of GCSE pupils. In particular, we focused on converting worded problems to...
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Answered by Francesca W. • Maths tutor
2964 Views

Write the equation x^2 + 6x - 40 = 0 in the form (x + a)^2 - b = 0 and then solve for x

(x 2 + 6x + 9) - 49 = 0 (x + 3)2 - 49 = 0 then to solve (x + 3) 2 = 49 x + 3 = +-7 x = -10 or x = 4
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Answered by Darragh S. • Maths tutor
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Solve the equation 2x^2 + 3x = 9

2x 2 + 3x = 92x 2 + 3x - 9 = 0(2x - 3)(x+3)2x-3 = 02x = 3x = 3/2x+3=0x=-3x = 3/2 or -3
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Answered by Sean N. • Maths tutor
3808 Views

Factorise fully x^3 - 10x^2 + 16x

The first thing we notice is that there is a common factor of x. Thus we can factor it out and get:x(x^2 - 10x + 16) This becomes much easier to deal with. We now focus on the equation in the brackets.We nee...
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Answered by Karina T. • Maths tutor
4013 Views

16cos30° - 5tan60° = √x. Find the value of x.

Split up the two terms: cos30° = (1/2)√3 and tan60° = √3 (from memorised values of cos and tan)Therefore 16cos30° = 8√3 and 5tan60° = 5√3 8√3 - 5√3 = 3√3 = √9 x √3 = √27x=27
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Answered by David G. • Maths tutor
3221 Views