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Solve (x+10)(x-16)=0

x+10=0x= -10x-16=0x= 16
ST
Answered by Sophie T. • Maths tutor
3427 Views

(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60. a = 4b = 60
AE
Answered by Aeron E. • Maths tutor
8629 Views

Solve the simultaneous equations : x ^2+2y=9, y=x+3 to find solutions for x and y.

We must use the substitution method for this question because the first equation is a quadratic. Take the more simple equation (the second one), and use that to substitute the value for y in to the first equ...
CR
Answered by Callum R. • Maths tutor
3735 Views

Solve the simultaneous equations: 2x+y=18 and x-y=6

To solve these simultaneous equations there are two different methods that could be used. The first one to try in this case is to start with rearranging one of the equations to get a value of y by itself. Fo...
EE
Answered by Ella E. • Maths tutor
4215 Views

Solve these simultaneous equations; 2y + x = 8, 4 + 4y = 8x

equation 1: 2y + x = 8 equation 2: 4 + 4y = 8xSolve by substitution ; simplify equation 1 2y + x = 8 x = 8 - 2y substitute into equation 2 4 + 4y = 8(8 - 2y)4 + 4y = 64 - 16y 4 + 20y = 64 20y = 60 y = 3 subs...
JH
Answered by Josephine H. • Maths tutor
4594 Views