Top answers

Solve, by method of substitution, the simultaneous equations: 5x+y=22 2x+y=10

Solve by substitution:5x + y = 22 (1)2x + y = 10 (2) First let us label the equations 1 and 2. In order to solve this set of equations we need to rearrange one of the equations so that we have one of the var...
AW
Answered by Amy W. • Maths tutor
5527 Views

Solve 8x+ 9 > 1 + 4x

8x + 9 > 1 + 4x . Bring all x values to the Left hand side by subtracting 4x from each side. 8x -4x +9 >1 = 4x +9 >1 Bring all numbers to the right hand side by subtracting 9 from each side 4x > ...
DE
Answered by Dominique E. • Maths tutor
3576 Views

Solve the following simulateous equations: 3x+y=11 and 2x+y=8

Minus 2x+y=8 from 3x+y=11 so that the y's cancel out (y-y=0). Then we get the equation 3x-2x=11-8.So we get x=3.We can substitute this value back into one the orginal equations: y=11-3(3)=2 - so y=2.We can c...
CG
Answered by Cameron G. • Maths tutor
3666 Views

Find the coordinates of the point of intersection of the lines y = 3x - 2 and x + 3y = 1.

(A-level Maths) Simultaneous equations: 1) y = 3x -2 2) x + 3y = 1 Substitute y = 3x - 2 into equation 2: x + 3y = 1x + 3(3x-2) = 1 1 mark x + 9x - 6 = 1 Expand brackets 10x - 6 = 1 Solve equation 10x = 1 + ...
KB
Answered by Kiran B. • Maths tutor
7882 Views

Simplify √ 12 + √ 75

First, the surds need to be simplified. Surds can be simplified by finding the highest square number that is a factor of the number in the square root.√12 = √(4 x 3) = √4 x √3 = 2√3√75 = √(25 x 3) = √25 x √3...
GR
Answered by Georgia R. • Maths tutor
18362 Views