Solve, by method of substitution, the simultaneous equations: 5x+y=22 2x+y=10

Solve by substitution:5x + y = 22 (1)2x + y = 10 (2)
First let us label the equations 1 and 2. In order to solve this set of equations we need to rearrange one of the equations so that we have one of the variables (x or y) equal to some expression, or in other words we need to make one of the variable the subject.
I am going to make y the subject in equation (1).
5x + y = 22 -5 -5 (we subtract 5 from both sides)
y= 22 -5x I'll call this equation (3).
So now I substitute (3) into (2) to get:
2x + (22 -5x) = 10
Rearrange to make x the subject:
22 -3x =103x = 12x = 4
Now we sub x=4 into equation (1).
5(4) + y = 2220 + y = 22y = 2
Answer x=4 y=2



AW
Answered by Amy W. Maths tutor

4533 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

X is a prime number higher than the square of 5 and lower than the square of 7. What are the smallest and largest possible values for X?


f(x) = 3x - 2a || g(x) = 2ax + 1 || fg(x) = 2x + b/2


Insert one pair of brackets so that this calculation is correct; 3 x 6 + 5 - 1 = 32


Using the following quadratic equation, find x: x2 + 3x -4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences