Solve the following simulateous equations: 3x+y=11 and 2x+y=8

Minus 2x+y=8 from 3x+y=11 so that the y's cancel out (y-y=0).
Then we get the equation 3x-2x=11-8.So we get x=3.We can substitute this value back into one the orginal equations: y=11-3(3)=2 - so y=2.We can check these values are correct by substituting them into the other equation: 2(3)+2=8.Hence our solutions are correct.

CG
Answered by Cameron G. Maths tutor

2959 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If 4x = 9y, and 2x + 5y = 95. What is the value of y^2 - x?


solve x^2 + 5x +6 = 0


What's the quadratic formula used for?


Write (9^8)/((9^5)^2) in its simplest form


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences