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Solve the quadratic: 3x^2+4x = 20 to find x.

Quadratic formula: where ax^2+bx+c =0, x = (-b±√(b^2-4ac))/2a.Rearrange the formula in the question to get 3x^2+4x-20 = 0.From the quadratic in the question we can see that a = 3, b = 4, c = -20.Therefore x ...
SF
Answered by Samuel F. • Maths tutor
6346 Views

Differentiate the following: 2x^2 + 3x -2

The correct answer is: 4x+3. The first part of the equation is differentiated by multiplying the power by the constant in front (2*2). The power is then reduced by one to x^1 (which is just x). This is repea...
TB
Answered by Tilly B. • Maths tutor
3846 Views

Solve the following for x: 2x^2-9x=5

The format of this question shows that it is a quadratic, which we can solve by factorising . We have 3 methods by which we can do this:First, we need to manipulate the equation into the form ax^2+bx+c. Subt...
NP
Answered by Noah P. • Maths tutor
4833 Views

Solve the following simultaneous equations: 3x + y = 11 2x + y = 8

Start off by determining which unknowns have the same coefficient- In this case it would be y as the coefficient of y is 1 in both equationsThen make both equations equal to y- So 3x+y= 11 would become y= 11...
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Answered by Amelia R. • Maths tutor
4670 Views

f(x) = 3x - 2a || g(x) = 2ax + 1 || fg(x) = 2x + b/2

fg(x) = 3(2ax +1) - 2a = 6ax + 3 - 2a6ax + 3 -2a = 2x + b/26a = 2 -> a = 1/33 - 2a = b/2 -> if a = 1/3 then: 3 - 2(1/3) = 9/3 - 2/3 = 7/3 7/3 * 2 = b = 14/3
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Answered by Elliott B. • Maths tutor
3612 Views