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Solve the equation p + 15 = 2(4p − 3)
Expand brackets: 8p-6. Move all values to one side: p - 8p + 15 + 6 = 0. Subtract p values and add normal numbers: -7p + 21 = 0. Move p values to other side: 21 = 7p. Divide through by 7: p = 21/7. p = 3.
LM
Answered by
Luke M.
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Maths tutor
5972 Views
X^2 -25 Find the solution to this equation.
candidate should recognise the equation is a difference between two squares. the next step is to factorise: square root of 25 is 5 (x-5)(x+5) = x^2-25 x= -5 x= 5
JD
Answered by
Jakub D.
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Maths tutor
3633 Views
If x^2 + 2y = -14 and y = 4x + 1 , by using the quadratic formula, find the possible values for x.
First the equation for y must be substituted into the first equation to give a quadratic equation in x. Rearrange this equation so that the left-hand side equals 0. Using the quadratic formula the possible v...
RW
Answered by
Rachael W.
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Maths tutor
2975 Views
a right-angled triangle has base 2x + 1, height h and hypotenuse 3x. show that h^2 = 5x^2 - 4x - 1
initially, explain Pythagorean's Theory --> a^2 + b^2 = c^2.explain c is the hypotenuse, a and b can be either base or height.using a as base and b as height, a = 2x+1. b = h. c = 3xsubstitute into formul...
MA
Answered by
Mohammad A.
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Maths tutor
3571 Views
Solve the following system of equations simultaneously to find the values of x, y and z. 2x+3y+4z=3, -x-y+z=1, 2x+y-z=0
First scale one of the equations so that upon addition or subtraction from another of the equations we cancel one of the 3 variables, next do this again replacing one of the equations used with the unused eq...
SA
Answered by
Shaun A.
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Maths tutor
3030 Views
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