a right-angled triangle has base 2x + 1, height h and hypotenuse 3x. show that h^2 = 5x^2 - 4x - 1
initially, explain Pythagorean's Theory --> a^2 + b^2 = c^2.explain c is the hypotenuse, a and b can be either base or height.using a as base and b as height, a = 2x+1. b = h. c = 3xsubstitute into formula:(2x+1)^2 + h^2 = 9x^2expanding brackets (using FOIL):4x^2 + 4x + 1 + h^2 = 9x^2rearranging so h^2 is the subject:h^2 = 5x^2 - 4x - 1
MA
Related Maths GCSE answers
All answers ▸Prove algebraically that (2n + 1) to the power of 2 - (2n-1) is an even number
Simplify: 2x +6y +2y - x
LOWER TIER a) Multiply the following out: (x+3)(x-4). b) Factorise the following equation into two bracket form: x^2+7x+12
The point P has coordinates (4, 5). The point Q has coordinates (a, b). A line perpendicular to PQ is given by the equation 5x+3y=11. Find an expression for b in terms of a.