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x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x 2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x 2 -6x-1...
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Answered by Jai P. • Maths tutor
3797 Views

How do Transformers work?

Transformers are two coils of wire, coiled around each side of an iron core (primary and secondary). The primary coil has a potential difference supplied to it that drives the alternating current through the...
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Answered by Niusha S. • Physics tutor
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How do you use Substitution to solve simultaneous equations?

For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. A g...
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Answered by Niusha S. • Maths tutor
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Name a composer from the Baroque period

Bach; Monteverdi; Handel; Scarlatti; Albinoni; Corelli
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Answered by Anita M. • Music tutor
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Work out 2^14 ÷ (2^9)^2 in its simplest form

2 14 ÷ (2 9 ) 2 I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled i.e. (2 9 ) 2 = 2 9x2 = 2 18 . ...
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Answered by Sion D. • Maths tutor
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