x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously
Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x2 -6x-16=0. Now we can factorise this to (x-8)(x+2)=0. from this we can deduce that x=8 and -2. We still need to find the answer to y since we know y=6x+2 (from first line) We can stustitute our answers to x in this. So When x=8, y= 50. When x=-2, y=-10
JP
Related Maths GCSE answers
All answers ▸What is Pythagoras' Theorem for finding the length of a side of a triangle?
A triangle has sides of 4cm and 5cm with the hypotenuse unknown. What is the length of the unknown side?
Solve the simultaneous equations: 2x + y = 18, x - y = 6
I want to buy 1 litre of milk. My options are to either buy 250ml bottles for £1 each or 500ml bottles for £1.50 each. Which is the cheapest way for me to buy 1 litre of milk?