x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x2 -6x-16=0. Now we can factorise this to (x-8)(x+2)=0. from this we can deduce that x=8 and -2. We still need to find the answer to y since we know y=6x+2 (from first line) We can stustitute our answers to x in this. So When x=8, y= 50. When x=-2, y=-10

JP

Related Maths GCSE answers

All answers ▸

Solve these simultaneous equations: 2x + 3y = 19 and x + 4y = 17.


The normal price of the pair of shoes is £28. In a sale the price is reduced by 35%. What is the new price of the shoes?


How do I find the equation of a straight line from a graph?


What is a good way to remember the sine, cosine and tangent rules of a triangle?