How do you use Substitution to solve simultaneous equations?

For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. A good method for this is to multiply each equation by the others x number, so for our equations we multiply 1x4 and 2x3 to give 12x = 16 - 8y (1) and 12x + 15y = 51 (2). Now you need to sub one into the other using the equivalent terms you have obtained. in our example we will sub 12x = 16 - 8y into 12x + 15y = 51 to get (16 - 8y) + 15y = 51. We now have to solve the equation normally: 15y - 8y = 51 - 16 --> 7y = 35 --> y = 5. Finally, sub the value you found into one of the original equations. For this we sub y = 5 into 1 to get 3x + 2(5) = 4 --> 3x + 10 = 4 --> 3x = -6 --> x = -2.

NS
Answered by Niusha S. Maths tutor

3291 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve the following simultaneous equation?


When would I use the quadratic formula?


Write the number 0.000000001 in standard form.


A circular table top has diameter 140 cm. The volume of the table top is 17,150π cmᶟ. Calculate the thickness of the table top


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning