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What factors should be taken into account when deciding which advertising media to use?

Since advertisement requires large sums of investment, businesses must make sure they 'get it right' from the beginning. The choice of media is an important decision, so businesses should consider the follow...
LD
5312 Views

A GCSE is graded out of 140 marks. 1/5 of these marks were given for coursework. The rest were divided between two reading and listening tests, with the marks split in the ratio 3:4 respectively. How many marks were given for the reading test?

140/5 = 28140 - 28 = 1123 + 4 = 7112/7 = 1616 x 3 = 48Answer: 48 (Would go through methods with student: order of thinking, dealing with ratio, long division)
WB
Answered by Will B. • Maths tutor
4550 Views

The equation 5x^2 + px + q = 0, where p and q are constants, has roots t and t+4. Show that p^2 = 20q + 400.

We know that if we have a polinomial of the form ax^2 + bx + c = 0, then:sum of the roots = -b/a and product of the roots = c/a Therefore: t + (t + 4) = -p/5 and t(t + 4) = q/5 Therefore: 2t + 4 = -p/5 so t ...
AB
Answered by Alexandra B. • Maths tutor
5278 Views

Solve the simultaneous equations: 3x+5y=19, 4x-2y=-18

For all simultaneous equations it is useful to number each one to keep your working clear and concise. In order to solve this we need to eliminate one of the variables (x or y) by manipulating the equations....
BW
Answered by Ben W. • Maths tutor
10196 Views

If 5x + 3y = 27 and 6x - 2y = 10, find x and y

5x + 3y = 27 (1)6x - 2y = 10 (2)Rearrange (1) to make x the subject.Subtracting - 3y from both sides gives5x = 27 - 3yDivide both sides by 5 givesx = (27 - 3y)/5Substitute (1) into (2) gives6(27 - 3y)/5 - 2y...
TA
Answered by Thomas A. • Maths tutor
4088 Views