Top answers


x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x 2 -(6x+2)=14. Open the brackets and subtract 14 from both sides. x 2 -6x-1...
JP
Answered by Jai P. Maths tutor
3745 Views

How do Transformers work?

Transformers are two coils of wire, coiled around each side of an iron core (primary and secondary). The primary coil has a potential difference supplied to it that drives the alternating current through the...
NS
Answered by Niusha S. Physics tutor
8645 Views

How do you use Substitution to solve simultaneous equations?

For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. A g...
NS
Answered by Niusha S. Maths tutor
3716 Views

Name a composer from the Baroque period

Bach; Monteverdi; Handel; Scarlatti; Albinoni; Corelli
AM
Answered by Anita M. Music tutor
4995 Views

Work out 2^14 ÷ (2^9)^2 in its simplest form

2 14 ÷ (2 9 ) 2 I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled i.e. (2 9 ) 2 = 2 9x2 = 2 18 . ...
SD
Answered by Sion D. Maths tutor
8126 Views