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Find and describe the stationary points of the curve y = x^2 + 2x - 8

Stationary points occur when the derivative is = 0Derivative: 2x + 2 = 0, so a stationary point occurs when x = -1y = 1 + 2 - 8 = -5Second derivative = 2Therefore, the stationary point (-1,2) is a minimum
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what is the site of gas exchange in the lungs

the alveoli (air sacs that follow from the bronchioles)
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Answered by Sito E. • Biology tutor
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what are isotopes and why do they have the same properties?

Isotopes are atoms of the same element that have the same proton number but different nucleon number. TRAIN OF THOUGHT --- Isotopes have the same proton number --- uncharged (neutral/unionised) molecules hav...
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Answered by Sito E. • Chemistry tutor
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Solve x^(-1/4) = 0.2

Get both sides in similar forms to make it easier to solve.1/x 1/4 = 1/5x 1/4 = 5x = 5 4 = 625
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A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4
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