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Solve x^2 + 2x = 48 for all values of x
First we need to rearrange so that it's all on one side of the equals sign:x 2 + 2x - 48 = 0 Now we have to find what will sum to make the coefficient of x (2) and multiplies together to get -48. So, the fac...
KC
Answered by
Ketan C.
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Maths tutor
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Let f(x)= x^2+4, and g(x)= 3x; Find g(f(1))
Suppose f(x)=x 2 +4 and g(x)=3xg(f(x)) would therefore be 3(x 2 +4) and that equals 3x 2 +12the next step would then be to substitute x with 1 to find the solution for (g(f(1)).By substituting 1 for x, you t...
MC
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Maxamilian C.
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Maths tutor
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In the arthmetic sequence, the first term is 3 and the fourth term is 12. Find the common difference (d) and the sum of the first 10 terms.
a. Finding du n = u 1 + (n-1)du 4 = u 1 + (4-1)d12 = 3 + 3dd = 3 b. Sum of first 10 termss n = n/2(2u 1 + (n-1)d)s 10 = 5(6 + 9d)s 10 = 30 + 45(3)s 10 = 165
RA
Answered by
Ruchi A.
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Maths tutor
1742 Views
The sixth term of an arithmetic sequence is 8 and the sum of the first 15 terms is 60. Find the common difference and list the first three terms.
Formulae to be used: n th term of an arithmetic sequence u n = u 1 + (n-1)d and sum of the first n terms of an arithmetic series S n = (n/2) * (2u 1 + (n-1)d) Substitute known values: u 1 + 5d = 8(15/2) * (2...
BC
Answered by
Bence C.
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Maths tutor
1881 Views
H(x)=(x^3)*(e^x) what is H'(x)
Using the product rule H(X) = f(x)*g(x) and H'(X) = f'(x)*g(x) + f(x)*g'(x) Where, in this case f(x) = x 3 and g(x) = e x We can easily determine the derivative of the above function.f'(x) = 3x 2 and g'(x) =...
AF
Answered by
Antonio F.
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Maths tutor
2100 Views
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