The sixth term of an arithmetic sequence is 8 and the sum of the first 15 terms is 60. Find the common difference and list the first three terms.

Formulae to be used: n^th term of an arithmetic sequence u_n= u₁ + (n-1)d and sum of the first n terms of an arithmetic series S_n = (n/2) * (2u₁ + (n-1)d) Substitute known values: u₁ + 5d = 8(15/2) * (2u₁ + 14d) = 60 Attempt to solve simultaneous equations, by eliminating u₁ and d, in turn, to get d = -2, and u₁ = 18, u₂ = 16, u₃ = 14.