H(x)=(x^3)*(e^x) what is H'(x)

Using the product rule H(X) = f(x)*g(x) and H'(X) = f'(x)*g(x) + f(x)*g'(x) Where, in this case f(x) = x³ and g(x) = e^x We can easily determine the derivative of the above function.f'(x) = 3x² and g'(x) = e^x.We now have all the components required to formulate the final answer. H'(x) = e^x*3x² + e^x*x³Which can finally be simplified to: H'(x) = e^xx² (3+x)