H(x)=(x^3)*(e^x) what is H'(x)
Using the product rule H(X) = f(x)*g(x) and H'(X) = f'(x)*g(x) + f(x)*g'(x) Where, in this case f(x) = x3 and g(x) = ex We can easily determine the derivative of the above function.f'(x) = 3x2 and g'(x) = ex.We now have all the components required to formulate the final answer. H'(x) = ex*3x2 + ex*x3Which can finally be simplified to: H'(x) = exx2 (3+x)
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