1715 Chemistry questions

How do i know what the major and minor products of the reaction between Hydrogen Bromide and Propene would be?

We would use something called Markovniov's rule. Essentially, the H+ ion (or proton) that is attracted to the electron dense double bond of the alkene, is added to the carbon that has the most Hydrogen atoms bonded to it. This creates the more stable carbocation intermediate (in this case a secondary carbocation) which has a lower activation energy, and therefore a faster reaction, hence a more favoured product. In this case, 2-Bromopropane is the major, and 1-Bromopropane is the minor product
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David Q.

55 minutes ago

Answered by David, Chemistry A Level tutor with MyTutor

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Define an isotope.

Compounds with the same molecular formula but have different structural formulas.
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Shivani S.

6 hours ago

Answered by Shivani, who has applied to tutor Chemistry GCSE with MyTutor

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What is the relative molecular mass of ammonia?

Ammonia is NH3.
Nitrogen has a relative atomic mass of 14.
Hydrogen has a relative atomic mass of 1.
14 + (3 x 1) = 17
Ammonia has a relative molecular mass of 17.
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Adam C.

7 hours ago

Answered by Adam, who has applied to tutor Chemistry GCSE with MyTutor

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What is the relative molecular mass of ammonia?

Ammonia is NH3.
Nitrogen has a relative atomic mass of 14.
Hydrogen has a relative atomic mass of 1.
14 + (3 x 1) = 17
Ammonia has a relative molecular mass of 17.
See more
Adam C.

8 hours ago

Answered by Adam, who has applied to tutor Chemistry GCSE with MyTutor

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What is the relative molecular mass of ammonia?

Ammonia is NH3.
Nitrogen has a relative atomic mass of 14.
Hydrogen has a relative atomic mass of 1.
14 + (3 x 1) = 17
Ammonia has a relative molecular mass of 17.
See more
Adam C.

9 hours ago

Answered by Adam, who has applied to tutor Chemistry GCSE with MyTutor

1 view

What is the relative molecular mass of ammonia?

Ammonia is NH3.
Nitrogen has a relative atomic mass of 14.
Hydrogen has a relative atomic mass of 1.
14 + (3 x 1) = 17
Ammonia has a relative molecular mass of 17.
See more
Adam C.

9 hours ago

Answered by Adam, who has applied to tutor Chemistry GCSE with MyTutor

1 view

Explain why Francium is the most reactive Group 1 element in terms of its electronic structure.

All group 1 elements have 1 electron in their outer shell, making this the electron that is involved in reactions. As you move down a group in the periodic table the number of shells increases, which means that the outer electron is further from the nucleus. As there are now more shells between the electron and the nucleus, the outer electron experiences more shielding and therefore less attraction to the nucleus. This means that the outer electron is more easily removed in Francium than other group 1 elements.
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Jordan F.

12 hours ago

Answered by Jordan, Chemistry GCSE tutor with MyTutor

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Explain why pure metals can be bent and shaped, whereas alloys cannot?

In pure metals the atoms are all the same size , hence the layers of atoms can slider over each other. However, in an alloy the different size atoms distory the layers in the structure hence it is difficult for the layers to slide over each other and be shaped.
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Ekaahh S.

12 hours ago

Answered by Ekaahh, Chemistry GCSE tutor with MyTutor

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Explain why Francium is the most reactive Group 1 element in terms of its electronic structure.

All group 1 elements have 1 electron in their outer shell, making this the electron that is involved in reactions. As you move down a group in the periodic table the number of shells increases, which means that the outer electron is further from the nucleus. As there are now more shells between the electron and the nucleus, the outer electron experiences more shielding and therefore less attraction to the nucleus. This means that the outer electron is more easily removed in Francium than other group 1 elements.
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Jordan F.

13 hours ago

Answered by Jordan, Chemistry GCSE tutor with MyTutor

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How do i know what the major and minor products of the reaction between Hydrogen Bromide and Propene would be?

We would use something called Markovniov's rule. Essentially, the H+ ion (or proton) that is attracted to the electron dense double bond of the alkene, is added to the carbon that has the most Hydrogen atoms bonded to it. This creates the more stable carbocation intermediate (in this case a secondary carbocation) which has a lower activation energy, and therefore a faster reaction, hence a more favoured product. In this case, 2-Bromopropane is the major, and 1-Bromopropane is the minor product
See more
David Q.

14 hours ago

Answered by David, Chemistry A Level tutor with MyTutor

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