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For a curve of equation 2ye^-3x -x = 4, find dy/dx

here the student needs to use both implicit differentiation and the product rule. I would differentiate term by term for this problem. for 2ye^-3x you have to use the proudct rule. uv differentiates to uv' +...
JB
Answered by Jack B. • Maths tutor
4396 Views

How do I factorise a quadratic equation?

A quadratic equation is one that takes the form.. ax 2 + bx +c = 0 Factorising an equation like this involves putting the equation into two brackets. The method varies slightly dependent on whether a = 1 or ...
BE
Answered by Beth E. • Maths tutor
4071 Views

Algebraic fractions

9/3x 2 - 3y 2 + x/xy - x 2 = 9/3(x 2 -y 2 ) + x/x(y-x) = 3/(x-y)(x+y) + 1/y-x = 3/(x-y)(x+y) - 1/x-y = 3-1(x+y)/(x-y)(x+y) = 3-x-y/(x-y)(x+y)
TL
Answered by Tristan L. • Maths tutor
3681 Views

Differentiate with respect to x: w=4x^2 + 3sin(2x)

We will split this up and differentiate each part separately. We can differentiate 4x 2 using our normal rules for differentiating; we multiply the coefficient by the power and then subtract one from the pow...
EM
Answered by Emma M. • Maths tutor
7414 Views

Given that y=(4x+1)^3*sin(2x) , find dy/dx

y=(4x+1)^3 sin(2x) - this is a product of two functions of x. It can be rewritten as y = u(x) v(x) ; where u(x) = (4x+1)^3 and v(x) = sin(2x) Using the product rule: dy/dx = u'(x) v(x) + v'(x) u(x) where the...
CD
Answered by Chris D. • Maths tutor
3905 Views