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y=6x+9 , 3y-18x+9=0 Are these lines parallel?

3y-18x+9=0 , 3y=18x-9 , y=6x-3 , Both lines have the same value for m which means they both have the same gradient and are therefore parallel.
SL
Answered by Sean L. • Maths tutor
3924 Views

There are 2 banks, Bank A and Bank B. Bank A provides compound interest of 1.3%. Bank B provides interest of 3.5% for the first year and then 0.7% for each extra year. James wants to invest £250. Which bank provides the most interest after 4 years?

Bank A: £250*(1.013^4) = £263.25570.... , Bank B: £250 1.035 (1.007^3) = £264.2218.... , 264>263 therefore Bank B provides more interest than Bank A
SL
Answered by Sean L. • Maths tutor
3445 Views

Find the x-intercepts of the graph y=x^2+2x

At the x-intercepts of the graph, the line crosses the x-axis. This means that the y-value at these points equals 0. We must therefore make x^2+2x equal to 0 and simplify the equation. x^2+2x = 0 is the same...
HH
Answered by Harry H. • Maths tutor
7269 Views

Differentiate y=e^(x)*sin(x) with respect to x

y=e^(x)*sin(x) Use the product rule: y'=uv'+vu' y=u*v Differentiate: u=e^(x) u'=e^(x) v=sin(x) v'=cos(x) Sub into the product rule: y'=e^(x)*cos(x)+e^(x)*sin(x) Take out a factor of e^(x): y'=e^(x)*(cos(x)+s...
AJ
Answered by Alexander J. • Maths tutor
6153 Views

Find dy/dx in terms of t of the parametric equations x=4e^-2t, y=4 - 2e^2t

x=4e -2t , y=4-2e 2t dy/dx = dy/dt * dt/dx dy/dt = -4e 2t dx/dt = -8e -2t dt/dx = -1/8 * e 2t dy/dx = (-4e 2t )(-1/8 * e 2t ) = 1/2 * e 4t dy/dx = 0.5e 4t
JM
Answered by Josh M. • Maths tutor
6101 Views