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Using a method that is not factorisation, solve the equation (x^2) + 3x -4 = 0. Hence, sketch the curve produced by the equation

One method that could be used to solve the equation is using the quadratic formula given by:x = ( -b ± (b 2 - 4ac) 0.5 ) / 2a where ax 2 + bx + c = 0Substituting our values into the (b 2 - 4ac) 0.5 first giv...
JW
Answered by Joseph W. Maths tutor
3212 Views

Complete the square of the equation below.

Q. Complete the square : x 2 + 4x - 12A. Completing the square is putting the given equation into the form (x + a) 2 + bFirst, a = the coefficient of x 2so in this case a = 4 = 2 Then to find b we calculate ...
VY
Answered by Victoria Y. Maths tutor
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If the quadratic equation kx^2+kx+1=0 has no real roots, what values of k are possible?

The solutions to quadratic equations, which are of the form ax^2+bx+c=0 with a≠0, are given by the Quadratic Formula: x= [-b+-sqrt(b^2-4ac)]/(2a). However, all real numbers, whether negative or not, square t...
Answered by Maths tutor
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Sketch the graph y = 2sin(4x)

We know that y=sinx is the sinusoidal graph that starts at the origin, with maxima at x = pi/2 with a value of 1, and a minima at x = 3pi/2 with a value of -1. The 4x inside the bracket means that all x valu...
GK
Answered by Gagan K. Maths tutor
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Solve algebraically the simultaneous equations (x^2) + (y^2) =25 and y - 3x = 13 (5 Marks).

The solution to simultaneous equations is where the values of x and y satisfy both equations. In this case, we need to find values of x and y that satisfy the equations x 2 + y 2 =25 and y - 3x = 13. If we n...
VG
Answered by Vaibhav G. Maths tutor
4563 Views