Using a method that is not factorisation, solve the equation (x^2) + 3x -4 = 0. Hence, sketch the curve produced by the equation

One method that could be used to solve the equation is using the quadratic formula given by:x = ( -b ± (b² - 4ac)^0.5) / 2a where ax² + bx + c = 0Substituting our values into the (b² - 4ac)^0.5 first gives (3² - 4 * 1 * (-4))^0.5 = (9 +16 )^0.5 = 25^0.5 which gives us 5.Using this result with the quadratic formula and substituting in further values gives us:x = ( -3 ± 5) / 2 which in turn means x = (-3 + 5) / 2 = 2 / 2 = 1 or x = (-3 - 5) / 2 = -8 / 2 = -4Completing the square could also be used here however this method is great due to the integer results in the calculations for this case!Finally, the solutions to x when the equation is equal to zero give us the points at which the curve cross the x axis. In this case they're at 1 and -4. The x² term is positive so we know the curve is a U shape (i.e. the curve has a minima rather than a maxima) and therefore the sketch would look like a positive quadratic curve (U shape) bisecting the x axis at 1 and -4. [Sketch would be drawn on whiteboard]