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If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle) (x-4)(x-5)=12 x 2 -9x+20=12 x 2 -9x+8=0 (x-8)(x-1)=0 x=8 or x=1 <---- x can't be 1 as we would get negative length and width x=8
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Answered by Simon M. • Maths tutor
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Factorise x^2+6x+8

Firstly, as it's highest term is x 2 , it must only have two factor brackets, so the answer has to look like (x + a) * (x + b).Then, to make 6x, we need the a and b term to be either 5 and 1, 4 and 2, or 3 a...
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Answered by Tom M. • Maths tutor
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Express (x+1)/2x + (2x+3)/(x+1) as one term

(x+1) 2 + 2x(2x+3) / 2x(x+1)
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Answered by Alex R. • Maths tutor
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Show that the two lines are parallel: L1: 4y = 24x +12, L2: 2y + 13 = 12x

Two lines are parallel when they have the same gradient. When the equation is written in the form: y = mx + c, m is the gradient. We need to arrange our equations in the form y = mx + c as this is the easies...
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Answered by Dominique T. • Maths tutor
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Simplify fully:6y2 +7y - 6y - 4 - 3y2

Simplify: 6y 2 +7y - 6y - 4 - 3y 2 The first step is to group the terms of the equation into y 2 terms, y terms and terms with no y: This gives, 6y 2 -3y 2 + 7y - 6y - 4 Next we are going to look at each ter...
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Answered by Dominique T. • Maths tutor
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