If a rectangle has length (x-4), width (x-5) and area 12 then what is the value of x?

length x width = area (as rectangle)(x-4)(x-5)=12x2-9x+20=12x2-9x+8=0(x-8)(x-1)=0x=8 or x=1 <---- x can't be 1 as we would get negative length and widthx=8

SM

Related Maths GCSE answers

All answers ▸

Make x the subject of, 4(x+1)/(x+2) = y


Solve (2x^2 - 3x - 14)/(x^2 + 6x + 8) = -6/(x+3).


The line y = x^2 -3x + 2 is reflected in the x-axis, find the equation of the new line that has been reflected.


A circle has a radius of 4cm. An isosceles triangle has a base of 8 cm and a height of 12 cm. Which shape has the greatest area?