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2x + y = 10 and 4y - 5x = 1, solve for x and y.

Rearrange one of the linear equations in order to have x or y written as an equation of the other. I.E 1) y =10 - 2x.Then substitute this value into the other equation: 4(10 - 2x) - 5x = 1, hence 39 = 13x wh...
NT
Answered by Nathan T. • Maths tutor
4960 Views

Solve the equation 3^(2x+1)=1000

We can use logarithms with base 3 to solve this equation.2x+1=log 3 10002x=log 3 (1000)-1x=0.5(log 3 (1000)-1)x=2.64
SD
Answered by Samuel D. • Maths tutor
5644 Views

Integrate 6/(e^x+2) between 1 and 0

By Trapezium Rule (with 5 segments)x 0 0.2 0.4 0.6 0.8 1y 2 1.8625 1.71830 1.56981 1.41994 1.27165≈1⁄2*(0.2) [2+1.27165+ 2( 1.8625 + 1.71830 + 1.56981 + 1.41994)]≈1⁄10 *16.41283 = 1.641By Substitution/ Parti...
CH
Answered by Christopher H. • Maths tutor
4945 Views

Binomially expand the equation (2+kx)^-3

(2+kx) -3 = (2 -3 )(1+kx/2) -3 = (2 -3 )(1+(-3)(kx/2) + [(-3)(-4)]/2! (kx/2) 2 + [(-3)(-4)(-5)]/3! (kx/2) 3 +... ) = 1⁄8 [1 -(3kx/2) + (12⁄2 k 2 x 2 /4) + (60⁄6 k 3 x 3 /8) + ...] = 1⁄8 [1 - (3⁄2 kx) + ( 3⁄2...
CH
Answered by Christopher H. • Maths tutor
9912 Views

Solve the simultaneous equations: 2x + y = 18, x - y =6.

There are 2 different ways to approach solving simultaneous equations: 1) making x or y the subject of one of the equations.2) addition or subtraction method.In this section, I will explain the first method....
JG
Answered by Jamini G. • Maths tutor
17853 Views