Solve the equation 3^(2x+1)=1000
We can use logarithms with base 3 to solve this equation.2x+1=log310002x=log3(1000)-1x=0.5(log3(1000)-1)x=2.64
SD
We can use logarithms with base 3 to solve this equation.2x+1=log310002x=log3(1000)-1x=0.5(log3(1000)-1)x=2.64