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Solve the simultaneous equations algebraically: y = x+19 AND y = x^2 + 4x +1.

We have one linear and one quadratic equation here. Since we have a quadratic, we will have two sets of solutions. Let's solve by substitution. Substitute equation (1) into equation (2), which yields:x + 19 ...
LD
Answered by Liam D. • Maths tutor
4529 Views

Three different brands of rice are on sale, which brand provides the best value for money? Their prices are: Brand A) 250g for £3.21, Brand B) 400g for £5.30, Brand C) 750g for £8.80

In order to compare the prices of each of these brands of rice, we will work out how much it costs to buy 100g of each brand - by using a consistent weight we can measure the prices against each other. The s...
GC
Answered by Gregory C. • Maths tutor
4158 Views

solve (y+1)^2 = 4

(y+1) 2 = 4. The power of two becomes a square root on the other side. Don't forget that this is plus or minus the square root of 4. Now we have y+1 = +- sqrt(4). We now have two equations to solve for y. y+...
JK
Answered by Jasper K. • Maths tutor
6276 Views

Factorise x^2 + 3x -28

[Method 1] The solutions need to add together to make 3 and multiply to make -28. For them to multiply and make a negative number one of the solutions must also be negative and the other positive (so there a...
AD
Answered by Austin D. • Maths tutor
7438 Views

Expand 5a(a+3b)

5a x a = 5a 2 5a x 3b =15ab 5a 2 + 15ab
MK
Answered by Mahnoor K. • Maths tutor
4846 Views