Factorise x^2 + 3x -28

[Method 1] The solutions need to add together to make 3 and multiply to make -28. For them to multiply and make a negative number one of the solutions must also be negative and the other positive (so there are two solutions total). Things that multiply to make -28 are 4 X -7, -4 X 7, 2 X -14, -2 X 14. If we add up each of these indivudally only 7 - 4 makes 3 which is what we want for the eqaution above. We can then write the answer as (x+7)(x-4).[Method 2] Use the quadratic formula to find the solutions to this equation are -7 and 4. From there we can form the brackets by reversing the +/- and writing (x+7)(x-4).

AD

Related Maths GCSE answers

All answers ▸

How do i solve simultaneous equations?


Find the roots of the equation y = 2x^2 + 5x + 2.


Use factorisation to simplify the following expression (x^2-9)/(x^2-4x+3)


What is (18)^1/2 -(8)^1/2 simplified?