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Find the location of the turning point of the following curve, y = x^2 + 6x - 7

Turning point is when dy/dx = 0 if y= x 2 + 6x - 7 dy/dx = 2x + 6 at turning point: 2x + 6 = 0 therefore: 2x = - 6 x coordinate: x = - 3 substitute into y to find y coordinate: y = (-3) 2 + 6(-3) -7 therefor...
HM
Answered by Hugo M. • Maths tutor
7162 Views

what is standard form?

standard form is a way of writing very large numbers or very small numbers in a condensed form. E.g. 1,600,000,000 can be written as 1.6x10^9
RA
Answered by Ruqia A. • Maths tutor
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Do I need to write down all of my working out?

Yes, in order to maximise the amount of marks you obtain you must write down all of your working as often the answer is only worth 1 mark whereas the working out makes up the rest of the marks. Always show y...
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Answered by Charlie C. • Maths tutor
6856 Views

By using the substitution, x = 2sin(y) find the exact value of integral sqrt(1/3(4-x^2)) dx with limits 0 and 1.

In order to calculate this integral we must use the sustitution provided. x=2siny. Firtsly I will differentiate to find the dx component of the integral, so dx/dy=2cosy hence, dx=2cosydy. Now for the limits ...
SS
Answered by Sara S. • Maths tutor
6502 Views

Show that the line y = x - 7 does not meet the circle (x + 2)^2 + y^2 = 33.

To find potential points of intersection between the line and the circle, we need to solve the equations simultaneously. So, we substitute y = x - 7 into the equation of the circle: (x + 2) 2 + y 2 = 33 (x +...
AI
Answered by Anastasios I. • Maths tutor
19664 Views