Find the location of the turning point of the following curve, y = x^2 + 6x - 7
Turning point is when dy/dx = 0
if y= x2 + 6x - 7
dy/dx = 2x + 6
at turning point: 2x + 6 = 0
therefore: 2x = - 6
x coordinate: x = - 3
substitute into y to find y coordinate: y = (-3)2 + 6(-3) -7
therefore: y = 9 -18 -7
y coordinate: y = -16
location of turning point: (-3,-16) //
HM
Related Maths A Level answers
All answers ▸Find the values of the constants a and b for which ax + b is a particular integral of the differential equation 2y' + 5y = 10x. Hence find the general solution of 2y' + 5y = 10x .
Differentiate 5x^3 + 4x^2 + 5x + 9
What is the exact answer to (1^3 + 2^3 + 3^3)^(0.5) ?
The equation x^2 + 3px + p = 0, where p is a non-zero constant, has equal roots. Find the value of p.