Find the location of the turning point of the following curve, y = x^2 + 6x - 7

Turning point is when dy/dx = 0

if y= x² + 6x - 7

dy/dx = 2x + 6

at turning point: 2x + 6 = 0

therefore: 2x = - 6

x coordinate: x = - 3

substitute into y to find y coordinate: y = (-3)² + 6(-3) -7

therefore: y = 9 -18 -7

y coordinate: y = -16

location of turning point: (-3,-16)  //