Top answers

Solve 2x+3 + ((4x-1)/2) = 10

Divide everything in the brackets by 2. 2x+3 + (2x -1/2) =10 Collect like terms (collect 'x' terms and collect numbers). 2x + 2x + 3 -1/2 = 10 Simplify like terms. 4x + 2 1/2 = 10 Rearrange so 'x's are on on...
LR
Answered by Lauren R. • Maths tutor
7344 Views

Find the determinant of a 2*2 matrix.

[1 -2; -5 -4] determinant = {1 * (-4)} - {-5 * (-2)} = -4 - 10 = -14
RA
Answered by Rishabh A. • Maths tutor
4681 Views

How do I find the roots of a quadratic equation?

A quadratic equation is an equations of the form: ax 2 + bx + c = 0 (1) where a is not 0. The ways of finding the roots are: quadratic formula, factorising, substituting, completing the square. Today, I'll c...
CM
Answered by Catriona M. • Maths tutor
4807 Views

Solve for x: 2x+3+((4x-1)/2)=10

Solve for x: 2x+3+((4x-1)/2)=10 First of all, move all the values on the left-hand side of the equation that are not in brackets over to the right-hand side of the equation so as to make the fraction (in bra...
LH
Answered by Luke H. • Maths tutor
4079 Views

Integrate dy/dx = 2x/(x^2-4)

Integrate dy/dx = 2x/(x 2 -4). We can answer this question using integration by substitution, where we set u = something in terms of x. In this case we are going to set u = x 2 -4 (the denominator). When we ...
WR
Answered by William R. • Maths tutor
12385 Views