Top answers


How do I find the roots of a quadratic equation?

A quadratic equation is an equations of the form: ax 2 + bx + c = 0 (1) where a is not 0. The ways of finding the roots are: quadratic formula, factorising, substituting, completing the square. Today, I'll c...
CM
Answered by Catriona M. Maths tutor
4898 Views

Solve for x: 2x+3+((4x-1)/2)=10

Solve for x: 2x+3+((4x-1)/2)=10 First of all, move all the values on the left-hand side of the equation that are not in brackets over to the right-hand side of the equation so as to make the fraction (in bra...
LH
Answered by Luke H. Maths tutor
4155 Views

Integrate dy/dx = 2x/(x^2-4)

Integrate dy/dx = 2x/(x 2 -4). We can answer this question using integration by substitution, where we set u = something in terms of x. In this case we are going to set u = x 2 -4 (the denominator). When we ...
WR
Answered by William R. Maths tutor
12488 Views

Solve algebraically: 6a + b = 16 5a - 2b = 19

b= 16-6a this will be your substitution. 5a- 2(16-6a)=19 now multiply out. 5a-32+12a=19 always remember positive and a negative multiplied is a negative. 17a=51 a= 51/17 = 3 now substitute a 6(3) +b = 16 b= -2
JD
Answered by Jade D. Maths tutor
3636 Views

Solve the quadratic equation x^2-6x+5=0

x 2 - 6x + 5 = 0. For simple quadratic equations such as this example we need to factorise the expression into 2 brackets: (x+a)(x+b) = 0. To find a and b we can expand the brackets to give: x 2 + (a+b)x +ab...
WR
Answered by William R. Maths tutor
12221 Views