Solve algebraically: 6a + b = 16 5a - 2b = 19
b= 16-6a this will be your substitution.
5a- 2(16-6a)=19 now multiply out.
5a-32+12a=19 always remember positive and a negative multiplied is a negative.
17a=51
a= 51/17 = 3
now substitute a
6(3) +b = 16
b= -2
JD
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