Solve algebraically: 6a + b = 16 5a - 2b = 19

b= 16-6a  this will be your substitution. 

5a- 2(16-6a)=19 now multiply out.

5a-32+12a=19 always remember positive and a negative multiplied is a negative.

17a=51

a= 51/17 = 3 

now substitute a 

6(3) +b = 16 

b= -2

JD
Answered by Jade D. Maths tutor

2832 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Which of the fractions 6/12, 9/8, 2/3 is equivalent to 12/18?


Prove that the square of an odd number is always 1 more than a multiple of 4


A cuboid of height 5 cm has a base of side 'a' cm. The longest diagonal of the cuboid is 'L' cm. Show that 'a' = SQRT[ (L^2 - 25)/2]


Cosine theorem?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences