Solve algebraically: 6a + b = 16 5a - 2b = 19

b= 16-6a  this will be your substitution. 

5a- 2(16-6a)=19 now multiply out.

5a-32+12a=19 always remember positive and a negative multiplied is a negative.

17a=51

a= 51/17 = 3 

now substitute a 

6(3) +b = 16 

b= -2

JD
Answered by Jade D. Maths tutor

3029 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the roots of 2x^2-5x-6=0 to 3dps


2x-4=6, find x.


Show that (x + 1)(x + 2)(x + 3) can be written in the form ax3 + bx2 + cx + d where a, b, c and d are positive integers.


Find the solutions of the equation x^2 - 2x - 8 =0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning