Solve for x: 2x+3+((4x-1)/2)=10

Solve for x: 2x+3+((4x-1)/2)=10 First of all, move all the values on the left-hand side of the equation that are not in brackets over to the right-hand side of the equation so as to make the fraction (in brackets) more easy to deal with. In order to do this you must perform the same calculation (that would remove these values on the left) to both sides of the equation (in this case subtract 2x and 3): (4x-1)/2= 10-2x-3 Repeat this concept by mulitplying both sides by 2 in order to get rid of the fraction: 4x-1= 20-4x-6 Now that the fraction is gone, it is a much easier problem to solve. Finish by bringing all multiples of x to the same side of the equation and then simplify so that it is clear what a single x value is equal to: 8x-1= 20-6 8x= 15 x= 15/8

LH
Answered by Luke H. Maths tutor

3346 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Edexcel 2017, Q8) A square, with sides of length x cm, is inside a circle. Each vertex of the square is on the circumference of the circle. The area of the circle is 49cm. Work out x.


For what values of k does the line y=kx-1 have two distinct points of intersection with the circle (x-2)^2+(y-3)^2=2?


2x+y=18, x-y=6; Solve the simultaneous equations


multiply out (2x-4)(x-2) and simplify.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences