Solve for x: 2x+3+((4x-1)/2)=10

Solve for x: 2x+3+((4x-1)/2)=10 First of all, move all the values on the left-hand side of the equation that are not in brackets over to the right-hand side of the equation so as to make the fraction (in brackets) more easy to deal with. In order to do this you must perform the same calculation (that would remove these values on the left) to both sides of the equation (in this case subtract 2x and 3): (4x-1)/2= 10-2x-3 Repeat this concept by mulitplying both sides by 2 in order to get rid of the fraction: 4x-1= 20-4x-6 Now that the fraction is gone, it is a much easier problem to solve. Finish by bringing all multiples of x to the same side of the equation and then simplify so that it is clear what a single x value is equal to: 8x-1= 20-6 8x= 15 x= 15/8

LH

Related Maths GCSE answers

All answers ▸

5 tins of soup have a total weight of 1750 grams. 4 tins of soup and 3 packets of soup have a total weight of 1490 grams. Work out the total weight of 3 tins of soup and 2 packets of soup.


The diagram shows a sector ORST of a circle with centre O. OR = OT = 10.4 cm. Angle ROT = 120°. (a) Calculate the length of the arc RST of the sector (3s.f)


what is 64 to the power of 2/3?


Factorise 2x^2 - 7x -4