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Find the coordinates of the turning point of the curve y=x^2+3x+7

We know that turning points occur when the gradient is equal to zero. Hence, we differentiate this curve. dy/dx = 2x+3 and we set this equal to zero. This gives 2x+3=0, we then rearrange to get 2x=-3 and so ...
RH
Answered by Rosie H. • Maths tutor
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Find the roots of the following equation x^2 + 6x + 5 = 0

There are a few ways to do this, firstly you notice that there is no coefficient in front of the x^2. This means you can factorise it with relative ease, by finding numbers that add to give 5 but multiply to...
CH
Answered by Callum H. • Maths tutor
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The equation of a curve is y=(x+3)^2 +5, what are the co-ordinates of the curve's turning point?

Differentiate y with respect to x:dy/dx = 2(x+3) = 2x+6When the above equation is equal to 0, this is where the turning point of the curve is.2x+6 = 02x = -6x = -3Therefore, at x = -3, the curve has a turnin...
HH
Answered by Harry H. • Maths tutor
4031 Views

How do I rearrange and make y the subject in equations such as "(y/4) - X = 1"?

The aim is to finish with an equation that looks like "y = .....". We want Y and X on separate sides.The main thing to remember is that whatever you do to one side of the equation, you also do to t...
DS
Answered by Dulcie S. • Maths tutor
3718 Views

What is the solution to the inequality shown? 3m + 5 > 2 (m-7)

So the first thing we would do is expand the right side: so multiply everything in the bracket by 2 to open it up -so it would become 2m - 14.3m + 5 > 2m -14Then we move all the like terms to one side (nu...
ZF
Answered by zeina f. • Maths tutor
4414 Views