Find the coordinates of the turning point of the curve y=x^2+3x+7
We know that turning points occur when the gradient is equal to zero. Hence, we differentiate this curve. dy/dx = 2x+3 and we set this equal to zero. This gives 2x+3=0, we then rearrange to get 2x=-3 and so x=-3/2. Placing this value of x back into the curve equation gives y=(-3/2)^2+3(-3/2)+7 and so y= 19/4. Therefore the coordinates of the turning point are (-3/2,19/4)
RH
Related Maths GCSE answers
All answers ▸The probability of obtaining heads on a biased coin is 0.4. The coin is tossed 600 times. Write down the mean number of heads and the standard deviation of the number of heads.
Work out 1 1/5 ÷ 3/4. Give your answer as a mixed number in it's simplest form
The numbers a,b,c and d satisfy the equations: a+2b+3c+4d=k and 4a=3b=2c=d. What is the smallest value of k for which a,b,c and d are positive integers?
Factorise and solve x^2 - 8x + 15 = 0