The equation of a curve is y=(x+3)^2 +5, what are the co-ordinates of the curve's turning point?

Differentiate y with respect to x:dy/dx = 2(x+3) = 2x+6When the above equation is equal to 0, this is where the turning point of the curve is.2x+6 = 02x = -6x = -3Therefore, at x = -3, the curve has a turning point. To find the y co-ordinate, substitute -3 into the original equation and solve for y:y=(-3+3)^2+5=5Therefore, the co-ordinates of the turning point are (-3,5)

HH
Answered by Harry H. Maths tutor

2974 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A solution to the equation 2x^2-3x-17=0 lies between 2&3 use method of trail and improvement to find the solution


Expand (2x+3) (3x-1)


Solve these simultaneous equations and find the values of x and y. Equation 1: 2x + y = 7 Equation 2: 3x - y = 8


Solve the equation (3x**2 + 8x + 4) = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences