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find the second degree equation that passes through the points: (0,1) (2,2) (1,0)

first of all we have to recognise the general form of the equation, similar to the equation of a line but we just have to add one more term due to the fact that it is a second degree equation: y=ax 2 +bx+c. ...
LG
Answered by Luca G. • Maths tutor
3525 Views

Integrate ln(x).

For this you’ll want to use the integration by parts method. In this the form u use is:integral of udv = uv - integral of vduTherefore we can rewrite the integral as ln(x)*1 labelling 1 as dv and ln(x) as u....
ES
Answered by Euan S. • Maths tutor
1878 Views

A right angled triangle has sides of length 3 and length 4, what is the length of the hypotenuse?

using pythagorus ( c^2 = b^2 + a^2) and plugging in 3 and 4 as a and b we get c^2 = 3^2 + 4^2 = 9 + 16 = 25. Taking the positive square root as sides can't be negative we get c = 5
KR
Answered by Kaitlyn R. • Maths tutor
3065 Views

Sketch the inequality x^2 - x - 12 > y on a set of axes.

First thing to note: this is a sketch question , and we're asked to sketch a quadratic (because there's an x 2 term). So we need to factorise (put the brackets in) to work out where it crosses the x-axis. Th...
TP
Answered by Tom P. • Maths tutor
3118 Views

Find the equation of the line perpendicular to y=2x-1 that passes through (2,0)

The first step is to remember that the equation of every straight line can be expressed as:y=mx+cSo we need to find the values of m and c. We have a rule that tells us the gradient of perpendicular lines- th...
WR
Answered by Will R. • Maths tutor
8484 Views