Find the equation of the line perpendicular to y=2x-1 that passes through (2,0)

The first step is to remember that the equation of every straight line can be expressed as:y=mx+cSo we need to find the values of m and c. We have a rule that tells us the gradient of perpendicular lines- the negative reciprocal rule! -So to find m, we find the negative reciprocal of 2. This gives us m=-0.5This is the stage at which lots of students get stuck. To find the value of c, we must first 'plug' our value of m back into the equation:y=-0.5x+cNow, we know that the point (2,0) is on the line, so we can write that:0=-0.5(2)+c0=-1+cSo adding 1 to both sides:c=1We are done! The answer is y=-0.5x+1

WR

Related Maths GCSE answers

All answers ▸

Expand and simplify (x+4)(x+5).


solve the simultaneous equation: 8x+2y=46; 7x+3y=47


Solve: (6x + 4)/(2x - 2) + 6 = 8


y is proportional to x^2. When y=45, x=3. Find a formula for y in terms of x.