Find the equation of the line perpendicular to y=2x-1 that passes through (2,0)

The first step is to remember that the equation of every straight line can be expressed as:y=mx+cSo we need to find the values of m and c. We have a rule that tells us the gradient of perpendicular lines- the negative reciprocal rule! -So to find m, we find the negative reciprocal of 2. This gives us m=-0.5This is the stage at which lots of students get stuck. To find the value of c, we must first 'plug' our value of m back into the equation:y=-0.5x+cNow, we know that the point (2,0) is on the line, so we can write that:0=-0.5(2)+c0=-1+cSo adding 1 to both sides:c=1We are done! The answer is y=-0.5x+1

WR
Answered by Will R. Maths tutor

7872 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Adam buys 4kg of sweets and pays £10 for them. Adam puts all of the sweers into bags with 250g in each bag. He sells the bags for 70p each. All the bags of sweets are sold, what is the percentage profit?


You are told that a straight line runs through 2 points: (1,1) and (2,3). What is the equation of the line?


How to calculate conditional probabilities? E.g, say we roll a fair standard six sided die, what is the probability we rolled a 2, given that the roll is even?


The equation of a curve is y = x^2 + ax + b where a and b are integers. The points (0,-5) and (5,0) lie on the curve. Find the coordinates of the turning point of the curve.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning