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Rectangle A has a length of 3y cm and a width of 2x cm. Rectangle B has a length of (y + 4)cm and a width of (x + 6)cm. Rectangle A has a perimeter of 94cm and Rectangle B has a perimeter of 56cm. Solve x and y and calculate the areas of each rectangle.

To calculate the perimeter of a shape, you have to add up the lengths of all of its sides. So:A: 3y + 2x + 3y + 2x = 94 ; B: (y + 4) + (x + 6) + (y + 4) +(x + 6) = 56Simplifying both equations give:4x + 6y =...
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Answered by Raghav A. • Maths tutor
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What is the mean of the numbers: 1, 7, 25, 9 and 34?

The mean of a group of numbers is found by dividing their sum by how many numbers there are. Mean=(1+7+25+9+34)/5=76/5=15.2
IR
Answered by Isabel R. • Maths tutor
4536 Views

Differentiate y=x(e^x)

Write as y=uv u=x v=e x du/dx=1 dv/dx=e x Using the product rule, dy/dx=v du/dx + u dv/dx So dy/dx=e x (1)+x(e x )=e x (1+x)
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Answered by Isabel R. • Maths tutor
5293 Views

How do I find the roots and and coordinates of the vertex of the graph y = 2x^2 + 4x - 8 ?

y = 2x^2 + 4x - 8y = 2( x^2 + 2x - 4)Completing the square:y = 2( (x+1)^2 - 1 - 4 )y = 2(x+1)^2 -10the vertex of graph lies at the minimum value of y, and this occurs when x = -1:y = 2(-1+1)^2 -10y = -10ther...
JA
Answered by Joe A. • Maths tutor
7781 Views

Solve the equation 3^(5x-2)=4^(6-x), and show that the solution can be written in the form log10(a)/log10(b).

So we have the equation initially in the form 3^(5x-2)=4^(6-x), and as the solution involves log10, then a sensible first move would be to take log10 of both sides, giving log10(3^(5x-2)) = log10(4^(6-x)). U...
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Answered by Eloise B. • Maths tutor
6532 Views