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solve sin(2x)=0.5. between 0<x<2pi

1)Take the inverse sin to take x from the sin(2x): 2x=arcsin(0.5). 2)Evaluate arcsin(0.5) to get pi/6: so 2x= pi/6 3)Dividing by 2 to simplify we get x=pi/12. 4)To find the second solution we note that (pi/2...
YZ
Answered by Yinglan Z. Maths tutor
24933 Views

Differentiate x^5 + 3x^2 - 17 with respect to x

When you are differentiating, use the formula: The differential of ax^n is (n*a) x^(n-1). Or in words: 'multiply by the power, then reduce the power by 1.' Hence for our question, x^5 differentiates to 5x^(5...
DL
Answered by David L. Maths tutor
4658 Views

Solve the simultaneous equations: 2x-3y = 24 and 6x+2y = -5

There are numerous alternative ways to solve these simultaneous equations. For this problem, one of the simplest methods is to multiply the first equation by 3, so that we get 6x in both equations: (2x - 3y)...
AS
Answered by Augustinas S. Maths tutor
4658 Views

Which Real values of x satisfy 3/ln(x) = ln(x) + 2?

The problem with this equation lies with the denominator on the left hand side. If we recall our graph of ln(x) however, we know that ln(x) is always positive and not equal to 0. Now we can safely multiply i...
MH
Answered by Mark H. Maths tutor
4834 Views

Where z is a complex number, what is the cartesian form of |Z-2+3i| = 1?

Z is simply a general complex number, which can be written as Z = x+iyHere |Z-2+3i| = 1 can be written as |Z-(2-3i)| = 1, which is just an expression for every Z whose distance from the point (2,-3i) is equa...
MH
Answered by Mark H. Maths tutor
10860 Views