Top answers

Solve the quadratic inequality x^2+x-6>/= 0.

First equate the equation to zero and solve it. To solve the quadratic equation, find the multiples that make '-6' and within this which have a total sum of 1. By this method we can figure out the two bracke...
AM
Answered by Anannya M. • Maths tutor
4042 Views

x/(2x-3) + 4/(x+1) =1 [5 mark question]

We have 2 fractions we want to get rid off to make it easier, so what we do is multiply both sides by the things we want to get rid off.In this case we multiply both sides by (2x-3)(x+1)This gives us x(x+1) ...
AJ
Answered by Abdul Jalil A. • Maths tutor
5019 Views

use the substitution u=2+ln(x) to show that int(e,1(ln(x)/x(2+ln(x)^2))dx)=p+ln(q) , where p and q are rational numbers.

So u=2+lnx, therefore du/dx=1/x , we can work out the new upper and new lower limit by substitute in e and 1 into 2+lnx , and we get 2+ln(e)=3 , 2+ln(1)=2Rearrange the differential we get dx=xdu , substitute...
Answered by • Maths tutor
5826 Views

Solve the quadratic inequality: x^2 - 5x + 4 < 0

x 2 -5x+4 &lt;0First we ignore the inequality and try to solve the equation x 2 -5x+4=0, which we do via factorising (x-4)(x-1)=0. x = 4 or x=1We draw the graph using our solution, going through the points o...
HH
Answered by Hariz H. • Maths tutor
14257 Views

Solve the following simultaneous equations to find x and y.

2x 2 - 2y = 282y - 4 = 12x y - 2 = 6xy = 6x + 2 Substitute y = 6x + 2 2x 2 - 2(6x + 2) = 282x 2 - 12x - 4 = 282(x 2 - 6x - 2) = 28x 2 - 6x - 2 = 14x 2 - 6x - 16 = 0(x - 8)(x + 2) = 0 if x = 8 then y = 50if x...
PD
Answered by Prahlad D. • Maths tutor
3713 Views