Top answers

3x + 12 = 24, solve for x.

Firstly, we need to make 'x' the subject of the equation. We do this by 'moving' everything that isn't an x over to the other side of the equation. When we do this, the main thing to remember is that whateve...
Answered by • Maths tutor
7048 Views

Find the equation of the tangent line to the curve y = 2x^2 - 4x + 3 at the point (3,9)

To find the equation of the tangent line to the curve y = 2x 2 - 4x + 3, we have to differentiate. Taking each part of the equation separately, we can calculate dy/dx = 4x - 4. By differentiating the equatio...
Answered by • Maths tutor
7909 Views

y = 1/x^2, differentiate y (taken from AQA 2018 past paper)

y = 1/x^2 is the same asy = x^-2 , now we can use the standard differentiation formula nx^n-1 to gety = -2x^-3y = -2/x^3
Answered by • Maths tutor
4227 Views

Solve this simultaneous equation using the process of elimination: -6x - 2y = 14 3x - 2y = 5

To solve using elimination, you need to use the following four steps:Step 1: make sure that both of the equations have opposite x terms or opposite y terms. Currently neither of the x terms in the two equati...
EB
Answered by Emily B. • Maths tutor
4041 Views

How do you complete the square for the question x^2 + 6x - 10 ?

the x squared is counted as A, the 6x is counted as B and -10 is C2) you halve the B term so in this case it would be 3x from the 6x and write it with an x in a bracket squared e.g. (x+3)^23) then you square...
AS
Answered by Amelia S. • Maths tutor
5041 Views