y = 1/x^2, differentiate y (taken from AQA 2018 past paper)
y = 1/x^2 is the same asy = x^-2 , now we can use the standard differentiation formula nx^n-1 to gety = -2x^-3y = -2/x^3
y = 1/x^2 is the same asy = x^-2 , now we can use the standard differentiation formula nx^n-1 to gety = -2x^-3y = -2/x^3
