How do you complete the square for the question x^2 + 6x - 10 ?
- the x squared is counted as A, the 6x is counted as B and -10 is C2) you halve the B term so in this case it would be 3x from the 6x and write it with an x in a bracket squared e.g. (x+3)^23) then you square the new B term which you have just created and minus it from the new equation you are forming e.g. (x+3)^2 -94) you then add the C term to the end of the new expression and add the two last terms together e.g. (x+3)^2 -19
AS
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