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A ball is released from rest at a height of 4m. At what speed does it hit the ground?

First write out information from the question.s=4m u=0m/s v=? a=9.8m/s 2 t=Choose correct "suvat" equation: v 2 =u 2 +2asSubstitute in known variables.Obtain v= 8.9m/s
MA
Answered by Molly A. • Maths tutor
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Express (x + 1)/((x^2)*(2x – 1)) in partial fractions

(x + 1)/((x^2)*(2x – 1)) = -3/x - 1/x^2 + 6/(2x-1)
DH
Answered by Douglas H. • Maths tutor
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solve: 4x^2 + 6x - 4 > 0

4x 2 + 6x - 4 > 0 2(2x 2 + 3x - 2) > 0 2(2x - 1)(x + 2) > 0 2x-1 = 0 --> 2x = 1 --> x = 0.5x+2 = 0 --> x = -2 x = 0.5
NH
Answered by Nicholas H. • Maths tutor
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Integrate 2x^4 - 4/sqrt(x) + 3 dx

First we will simplify 4/sqrt(x) so it is easier to integrate.sqrt(x) is equal to x 1/2 , therefore 4/sqrt(x) = 4/x 1/2 .We bring up x 1/2 so 4/x 1/2 becomes 4x -1/2 .So now we will integrate the simplified ...
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Answered by Maleehah A. • Maths tutor
8473 Views

2x + 5y =33 x+3y = 19

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Answered by Sen H. • Maths tutor
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